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#796 Rotate String

Posted on January 21, 2022January 21, 2022 By thecodepathshala 4 Comments on #796 Rotate String

Given two strings s and goal, return true if and only if s can become goal after some number of shifts on s.

A shift on s consists of moving the leftmost character of s to the rightmost position.

  • For example, if s = "abcde", then it will be "bcdea" after one shift.

Example 1:

Input: s = "abcde", goal = "cdeab"
Output: true

Example 2:

Input: s = "abcde", goal = "abced"
Output: false

Solution :

bool rotateString(string s, string goal) {
        string tmp = s+s;
        if(s.length() != goal.length())
            return false;
        
        if(tmp.find(goal) != string::npos)
            return true;
        return false;
    }

Complete Code:

/*
Given two strings s and goal, return true if and only if s can become goal after some number of shifts on s.
A shift on s consists of moving the leftmost character of s to the rightmost position.
For example, if s = "abcde", then it will be "bcdea" after one shift.

Example 1:
Input: s = "abcde", goal = "cdeab"
Output: true

Example 2:
Input: s = "abcde", goal = "abced"
Output: false
*/
#include <bits/stdc++.h>
using namespace std;

bool checkRotation(string s1, string s2) {
	string tmp = s1+s1;
	if(s1.length() != s2.length())
		return false;
	cout << tmp << " : " << s2 << endl;
	if(tmp.find(s2) != string::npos)
		return true;
	return false;
}

int main()
{
	string str1 = "abcde";
	string str2 = "abced";
	cout << checkRotation(str1, str2) << endl;
	return 0;
}
Algo, Competitive Programming, DS & Algo, GFG, Leetcode Problems Tags:coding interview, easy, leetcode, string

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