Given an array of integers nums which is sorted in ascending order, and an integer target, write a function to search target in nums. If target exists, then return its index. Otherwise, return -1.
You must write an algorithm with O(log n) runtime complexity.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9 Output: 4 Explanation: 9 exists in nums and its index is 4
Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2 Output: -1 Explanation: 2 does not exist in nums so return -1
Solution :
class Solution {
public:
int search(vector<int>& nums, int target) {
int low= 0, high = nums.size()-1;
while(low <= high)
{
int mid = (low+high)/2;
if(nums[mid] == target) {
return mid;
}
else if(target <= nums[mid]) {
high = mid-1;
}
else {
low = mid+1;
}
}
return -1;
}
};
Link : https://leetcode.com/problems/binary-search/?envType=study-plan&id=algorithm-i
