C program to find all roots of a quadratic equation using switch case

Example
Input

Input a: 4
Input b: -2
Input c: -10

Output

Root1: 1.85
Root2: -1.35

/**
 * C program to find all roots of a quadratic equation using switch case
 */

#include <stdio.h>
#include <math.h> /* Used for sqrt() */

int main()
{
    float a, b, c;
    float root1, root2, imaginary;
    float discriminant;

    printf("Enter values of a, b, c of quadratic equation (aX^2 + bX + c): ");
    scanf("%f%f%f", &a, &b, &c);

    /* Calculate discriminant */
    discriminant = (b * b) - (4 * a * c);


    /* Compute roots of quadratic equation based on the nature of discriminant */
    switch(discriminant > 0)
    {
        case 1:
            /* If discriminant is positive */
            root1 = (-b + sqrt(discriminant)) / (2 * a);
            root2 = (-b - sqrt(discriminant)) / (2 * a);

            printf("Two distinct and real roots exists: %.2f and %.2f", 
                    root1, root2);
            break;

        case 0:
            /* If discriminant is not positive */
            switch(discriminant < 0)
            {
                case 1:
                    /* If discriminant is negative */
                    root1 = root2 = -b / (2 * a);
                    imaginary = sqrt(-discriminant) / (2 * a);

                    printf("Two distinct complex roots exists: %.2f + i%.2f and %.2f - i%.2f", 
                            root1, imaginary, root2, imaginary);
                    break;

                case 0:
                    /* If discriminant is zero */
                    root1 = root2 = -b / (2 * a);

                    printf("Two equal and real roots exists: %.2f and %.2f", root1, root2);

                    break;
            }
    }

    return 0;
}

/*
Output :

Enter values of a, b, c of quadratic equation (aX^2 + bX + c): 4 -2 -10
Two distinct and real roots exists: 1.85 and -1.35
*/