GFG PTOD | 29 Jan | Implement Pow

double power(double b, int e) {
        // code here
        int n = abs(e);
        double res = 1.0;
        while(n>0) {
            if(n%2 == 0) {
                b *=b;
                n=n/2;
            } else {
                res *= b;
                n--;
            }
        }
        if(e<0) res = double(1.0)/res;
        return res;
    }