Example
Input
Input hexadecimal: 1A
Output
Decimal number: 26
Logic to convert Hexadecimal to Binary number system
Hexadecimal to binary conversion is divided in three steps.
- Extract each hex digits separately.
- Find the binary of each extracted hex digit.
- Store the binary equivalent of extracted hexadecimal number to final bin variable.
Repeat the above three steps till all hexadecimal digits are processed.
Hexadecimal to binary conversion table
Decimal | Binary | Hexadecimal |
---|---|---|
0 | 0000 | 0 |
1 | 0001 | 1 |
2 | 0010 | 2 |
3 | 0011 | 3 |
4 | 0100 | 4 |
5 | 0101 | 5 |
6 | 0110 | 6 |
7 | 0111 | 7 |
8 | 1000 | 8 |
9 | 1001 | 9 |
10 | 1010 | A |
11 | 1011 | B |
12 | 1100 | C |
13 | 1101 | D |
14 | 1110 | E |
15 | 1111 | F |
/**
* C program to convert Hexadecimal to binary number system
*/
#include <stdio.h>
#include <string.h>
int main()
{
char hex[17], bin[65] = "";
int i = 0;
/* Input hexadecimal number from user */
printf("Enter any hexadecimal number: ");
gets(hex);
/* Extract first digit and find binary of each hex digit */
for(i=0; hex[i]!='\0'; i++)
{
switch(hex[i])
{
case '0':
strcat(bin, "0000");
break;
case '1':
strcat(bin, "0001");
break;
case '2':
strcat(bin, "0010");
break;
case '3':
strcat(bin, "0011");
break;
case '4':
strcat(bin, "0100");
break;
case '5':
strcat(bin, "0101");
break;
case '6':
strcat(bin, "0110");
break;
case '7':
strcat(bin, "0111");
break;
case '8':
strcat(bin, "1000");
break;
case '9':
strcat(bin, "1001");
break;
case 'a':
case 'A':
strcat(bin, "1010");
break;
case 'b':
case 'B':
strcat(bin, "1011");
break;
case 'c':
case 'C':
strcat(bin, "1100");
break;
case 'd':
case 'D':
strcat(bin, "1101");
break;
case 'e':
case 'E':
strcat(bin, "1110");
break;
case 'f':
case 'F':
strcat(bin, "1111");
break;
default:
printf("Invalid hexadecimal input.");
}
}
printf("Hexademial number = %s\n", hex);
printf("Binary number = %s", bin);
return 0;
}
/*
Output :
Enter any hexadecimal number: 1a
Hexademial number = 1a
Binary number = 00011010
*/