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TCP DSA 75 TCP DSA 150 Top 351 DSA Questions Top 351 DSA Questions Tracker 🎯 Interview Preparation Top 351 DSA Questions Track your progress, add notes, count revisions, and find which companies ask each problem. 351 Total Easy: 102 Medium: 182 Hard: 67 10 Topics Problems Solved 0 / 351 Easy: 0/102 Medium: 0/182 Hard: 0/67…
TCP HLD 50 System Design HLD — 101 Topics Tracker HLD 101 System Design Prep Tracker ⚙ HLD 101 System Design Tracker Complete preparation list for High-Level Design interviews — company tags, difficulty, revision tracking, notes & reference links. 0 Topics 0 Completed 0 Revised 3× 0 Remaining 0% Progress 0 / 0 done0% Easy…
TCP HLD 101 System Design HLD — 50 Topics Tracker HLD System Design Tracker ⚙ HLD System Design Tracker High-Level Design topics for Software Engineering interviews — company tags, difficulty, revision tracking & reference links. 0 Topics 0 Completed 0 Revised 3× 0% Progress 0 / 0 done0% All Easy Medium Hard Completed Pending Category:…
TCP DSA 75 TCP DSA 351 TCP DSA150 ✅ Top 150 Questions – Structured DSA Preparation for Coding Interviews TCP DSA150 — Interview Tracker TCP DSA150 NeetCode 150 — your personal interview preparation tracker. Track progress, revisions, and notes in one place. 0 Solved 150 Visible 0 Revisions 0% Complete 0 / 150 solved 0%…
TCP DSA 150 TCP DSA 351 TCP DSA 75 ✅ Structured DSA Preparation for Coding Interviews TCP DSA 75 — Interview Tracker TCP DSA75 Tracker Track your progress, revision count, notes, and the companies that ask each problem. 75 Problems 0 Solved 0 Revisions 0% Complete 0 / 75 solved0% All Easy Medium Hard ✓…
Problem:Given a string s, find the length of the longest substring without repeating characters. Example: 🔥 Best Approach (HashMap Jump Optimization) Instead of removing one by one,jump left directly to the correct position. ⚙️ Algorithm 💻 C++ Optimal Solution 🔍 Dry Run Input: right char left window ans 0 a 0 a 1 1 b…
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You are given a 0-indexed array of integers nums of length n. You are initially positioned at nums[0]. Each element nums[i] represents the maximum length of a forward jump from index i. In other words, if you are at nums[i], you can jump to any nums[i + j] where: 0 <= j <= nums[i] and i + j < n Return the minimum number of jumps to reach nums[n -…
You are given an integer array nums. You are initially positioned at the array’s first index, and each element in the array represents your maximum jump length at that position. Return true if you can reach the last index, or false otherwise. Example 1: Input: nums = [2,3,1,1,4] Output: true Explanation: Jump 1 step from index 0 to 1, then 3…
Given an integer array nums, rotate the array to the right by k steps, where k is non-negative. Example 1: Example 2: Solutions 1 : Solutions 2 : Solution 3:
Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array. Example 1: Input: nums = [3,2,3] Output: 3 Example 2: Input: nums = [2,2,1,1,1,2,2] Output: 2 Solution 1 Solution 2